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Home»Forum»What happens to a MOSFET as the drain-source voltage increases?
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What happens to a MOSFET as the drain-source voltage increases?

siliconvlsiBy siliconvlsiSeptember 2, 2023Updated:May 17, 2024No Comments3 Mins Read
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The Saturation Region

As the drain-source voltage (VDS) is further increased in a MOSFET, a critical condition is eventually reached where the assumption that the channel voltage is larger than the threshold voltage (VT) along the entire channel length no longer holds. This condition occurs when the difference between the gate-source voltage (VGS) and the local voltage along the channel (V(x)) becomes less than the threshold voltage (VGS – V(x) < VT).

NMOS transistor under Saturation Region

When this happens, the induced charge in the channel becomes zero, and the conducting channel either diminishes in thickness or is entirely pinched off. This phenomenon is illustrated in Figure 1, which exaggerates the gradual reduction in channel thickness from the source to the drain until pinch-off occurs. Notably, the absence of a conducting channel near the drain region is a key characteristic of this behavior.

For this phenomenon to occur, it’s crucial that the pinch-off condition is met at the drain region, specifically when V(x) equals VT at the drain end. In this state, the transistor is said to be in the saturation region, and the describing the drain current no longer holds.

In the saturation mode, the voltage difference over the induced channel (from the pinch-off point near the drain to the source) remains constant at VGS – VT. Consequently, the drain current remains constant or saturates. Replacing VDS with VGS – VT, yields the drain current for the saturation mode. Importantly, in the saturation region, the drain current becomes independent of VDS, which means it remains relatively constant despite variations in VDS.

This behavior is significant for MOSFET operation, as it enables precise control of the drain current using the gate-source voltage (VGS). Furthermore, the drain current exhibits a squared dependence on VGS, highlighting the MOSFET’s ability to amplify signals in this operational mode.


What condition leads to the pinching off of the conducting channel in a MOSFET?

Answer: The conducting channel in a MOSFET begins to pinch off when the condition VGS – V(x) < VT is met, where V(x) is the voltage along the channel from the source to the drain. When this condition is satisfied, the induced charge becomes zero, causing the channel to disappear or pinch off.

How is the saturation region of a MOSFET defined?

Answer: The saturation region of a MOSFET occurs when the conducting channel is pinched off at the drain end. In this region, the drain current remains constant (saturates) and is no longer a function of the drain-source voltage (VDS).

What is the significance of the pinch-off condition in a MOSFET?

Answer: The pinch-off condition signifies the point at which the conducting channel narrows and eventually disappears as the drain-source voltage is increased. It is crucial for the MOSFET to operate in its saturation region.

How does the drain current behave in the saturation region of a MOSFET?

Answer: In the saturation region, the drain current remains constant and is independent of the drain-source voltage (VDS). The drain current in the saturation mode is directly proportional to the square of the gate-source voltage (VGS – VT).

What happens to the thickness of the conducting channel in a MOSFET as the drain-source voltage increases?

Answer: As the drain-source voltage increases, the thickness of the conducting channel gradually reduces from the source to the drain until pinch-off occurs, especially near the drain region. In the saturation region, the drain current is no longer dependent on VDS; instead, it remains constant due to the fixed voltage difference over the induced channel (VGS – VT).

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